Optimal. Leaf size=173 \[ -\frac{7986105 \sqrt{5 x+3}}{845152 \sqrt{1-2 x}}+\frac{698295 \sqrt{5 x+3}}{21952 \sqrt{1-2 x} (3 x+2)}+\frac{6621 \sqrt{5 x+3}}{1568 \sqrt{1-2 x} (3 x+2)^2}+\frac{263 \sqrt{5 x+3}}{392 \sqrt{1-2 x} (3 x+2)^3}+\frac{3 \sqrt{5 x+3}}{28 \sqrt{1-2 x} (3 x+2)^4}-\frac{24922335 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{153664 \sqrt{7}} \]
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Rubi [A] time = 0.0604215, antiderivative size = 173, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.231, Rules used = {103, 151, 152, 12, 93, 204} \[ -\frac{7986105 \sqrt{5 x+3}}{845152 \sqrt{1-2 x}}+\frac{698295 \sqrt{5 x+3}}{21952 \sqrt{1-2 x} (3 x+2)}+\frac{6621 \sqrt{5 x+3}}{1568 \sqrt{1-2 x} (3 x+2)^2}+\frac{263 \sqrt{5 x+3}}{392 \sqrt{1-2 x} (3 x+2)^3}+\frac{3 \sqrt{5 x+3}}{28 \sqrt{1-2 x} (3 x+2)^4}-\frac{24922335 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{153664 \sqrt{7}} \]
Antiderivative was successfully verified.
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Rule 103
Rule 151
Rule 152
Rule 12
Rule 93
Rule 204
Rubi steps
\begin{align*} \int \frac{1}{(1-2 x)^{3/2} (2+3 x)^5 \sqrt{3+5 x}} \, dx &=\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{1}{28} \int \frac{\frac{103}{2}-120 x}{(1-2 x)^{3/2} (2+3 x)^4 \sqrt{3+5 x}} \, dx\\ &=\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{1}{588} \int \frac{\frac{14787}{4}-11835 x}{(1-2 x)^{3/2} (2+3 x)^3 \sqrt{3+5 x}} \, dx\\ &=\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{6621 \sqrt{3+5 x}}{1568 \sqrt{1-2 x} (2+3 x)^2}+\frac{\int \frac{\frac{1180305}{8}-695205 x}{(1-2 x)^{3/2} (2+3 x)^2 \sqrt{3+5 x}} \, dx}{8232}\\ &=\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{6621 \sqrt{3+5 x}}{1568 \sqrt{1-2 x} (2+3 x)^2}+\frac{698295 \sqrt{3+5 x}}{21952 \sqrt{1-2 x} (2+3 x)}+\frac{\int \frac{-\frac{21066255}{16}-\frac{73320975 x}{4}}{(1-2 x)^{3/2} (2+3 x) \sqrt{3+5 x}} \, dx}{57624}\\ &=-\frac{7986105 \sqrt{3+5 x}}{845152 \sqrt{1-2 x}}+\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{6621 \sqrt{3+5 x}}{1568 \sqrt{1-2 x} (2+3 x)^2}+\frac{698295 \sqrt{3+5 x}}{21952 \sqrt{1-2 x} (2+3 x)}-\frac{\int -\frac{5757059385}{32 \sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx}{2218524}\\ &=-\frac{7986105 \sqrt{3+5 x}}{845152 \sqrt{1-2 x}}+\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{6621 \sqrt{3+5 x}}{1568 \sqrt{1-2 x} (2+3 x)^2}+\frac{698295 \sqrt{3+5 x}}{21952 \sqrt{1-2 x} (2+3 x)}+\frac{24922335 \int \frac{1}{\sqrt{1-2 x} (2+3 x) \sqrt{3+5 x}} \, dx}{307328}\\ &=-\frac{7986105 \sqrt{3+5 x}}{845152 \sqrt{1-2 x}}+\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{6621 \sqrt{3+5 x}}{1568 \sqrt{1-2 x} (2+3 x)^2}+\frac{698295 \sqrt{3+5 x}}{21952 \sqrt{1-2 x} (2+3 x)}+\frac{24922335 \operatorname{Subst}\left (\int \frac{1}{-7-x^2} \, dx,x,\frac{\sqrt{1-2 x}}{\sqrt{3+5 x}}\right )}{153664}\\ &=-\frac{7986105 \sqrt{3+5 x}}{845152 \sqrt{1-2 x}}+\frac{3 \sqrt{3+5 x}}{28 \sqrt{1-2 x} (2+3 x)^4}+\frac{263 \sqrt{3+5 x}}{392 \sqrt{1-2 x} (2+3 x)^3}+\frac{6621 \sqrt{3+5 x}}{1568 \sqrt{1-2 x} (2+3 x)^2}+\frac{698295 \sqrt{3+5 x}}{21952 \sqrt{1-2 x} (2+3 x)}-\frac{24922335 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{3+5 x}}\right )}{153664 \sqrt{7}}\\ \end{align*}
Mathematica [A] time = 0.0696951, size = 95, normalized size = 0.55 \[ \frac{-7 \sqrt{5 x+3} \left (1293749010 x^4+1998242055 x^3+482249808 x^2-491393004 x-205593328\right )-274145685 \sqrt{7-14 x} (3 x+2)^4 \tan ^{-1}\left (\frac{\sqrt{1-2 x}}{\sqrt{7} \sqrt{5 x+3}}\right )}{11832128 \sqrt{1-2 x} (3 x+2)^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.015, size = 305, normalized size = 1.8 \begin{align*}{\frac{1}{23664256\, \left ( 2+3\,x \right ) ^{4} \left ( 2\,x-1 \right ) } \left ( 44411600970\,\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) \sqrt{7}{x}^{5}+96225135435\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{4}+59215467960\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{3}+18112486140\,{x}^{4}\sqrt{-10\,{x}^{2}-x+3}-6579496440\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ){x}^{2}+27975388770\,{x}^{3}\sqrt{-10\,{x}^{2}-x+3}-17545323840\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) x+6751497312\,{x}^{2}\sqrt{-10\,{x}^{2}-x+3}-4386330960\,\sqrt{7}\arctan \left ( 1/14\,{\frac{ \left ( 37\,x+20 \right ) \sqrt{7}}{\sqrt{-10\,{x}^{2}-x+3}}} \right ) -6879502056\,x\sqrt{-10\,{x}^{2}-x+3}-2878306592\,\sqrt{-10\,{x}^{2}-x+3} \right ) \sqrt{3+5\,x}\sqrt{1-2\,x}{\frac{1}{\sqrt{-10\,{x}^{2}-x+3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{5 \, x + 3}{\left (3 \, x + 2\right )}^{5}{\left (-2 \, x + 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.82248, size = 437, normalized size = 2.53 \begin{align*} -\frac{274145685 \, \sqrt{7}{\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )} \arctan \left (\frac{\sqrt{7}{\left (37 \, x + 20\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{14 \,{\left (10 \, x^{2} + x - 3\right )}}\right ) - 14 \,{\left (1293749010 \, x^{4} + 1998242055 \, x^{3} + 482249808 \, x^{2} - 491393004 \, x - 205593328\right )} \sqrt{5 \, x + 3} \sqrt{-2 \, x + 1}}{23664256 \,{\left (162 \, x^{5} + 351 \, x^{4} + 216 \, x^{3} - 24 \, x^{2} - 64 \, x - 16\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 3.93325, size = 547, normalized size = 3.16 \begin{align*} \frac{4984467}{4302592} \, \sqrt{70} \sqrt{10}{\left (\pi + 2 \, \arctan \left (-\frac{\sqrt{70} \sqrt{5 \, x + 3}{\left (\frac{{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \,{\left (\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}\right )}}\right )\right )} - \frac{64 \, \sqrt{5} \sqrt{5 \, x + 3} \sqrt{-10 \, x + 5}}{924385 \,{\left (2 \, x - 1\right )}} + \frac{99 \,{\left (4411181 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{7} + 2388710520 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{5} + 506212728000 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{3} + 38676680000000 \, \sqrt{10}{\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}\right )}}{537824 \,{\left ({\left (\frac{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}{\sqrt{5 \, x + 3}} - \frac{4 \, \sqrt{5 \, x + 3}}{\sqrt{2} \sqrt{-10 \, x + 5} - \sqrt{22}}\right )}^{2} + 280\right )}^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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